Weather Station Project #27 - Took some samples through material

This morning I was out in the yard setting up an experiment.  I connected the Solar Radiation/UV Sensor setup to a POE enabled cable connected to a Ethernet over Power Line adapter.  The other Power Line adapter I plugged into my computer downstairs in the computer room.  This adapter was plugged into a Pers VLAN connector on one of my GS108Ts.  By doing this, I was able to connect to the sensor setup using my laptop on the porch through wi-fi.  I am going to leave the connection downstairs so that I will be able to use the Power Line adapter in other VLANS as necessary.  It was neat to get it working.  Here is a picture of the parts on my porch table.

The values of the data that I took was as follows:

results with no cover in bright sunlight

{ "tslLUX":"65536.00", "uvVIS":"1677.00", "uvIR":"13354.00", "uvUVRaw":"761.00", "uvUV":"7.61" }

reading from site was 12.0 for UV

Kingstowne says 7.4 UV, 835 watts/m^2

results with plastic cover in bright sunlight

{ "tslLUX":"65536.00", "uvVIS":"1594.00", "uvIR":"12876.00", "uvUVRaw":"716.00", "uvUV":"7.16" }

results with polycarbonate in bright sunlight

{ "tslLUX":"65536.00", "uvVIS":"1600.00", "uvIR":"13228.00", "uvUVRaw":"720.00", "uvUV":"7.20" }

Kingstowne says 6.9 UV, 796 watts/m^2

results with soda glass in bright sunlight

{ "tslLUX":"65536.00", "uvVIS":"1627.00", "uvIR":"12333.00", "uvUVRaw":"734.00", "uvUV":"7.34" }

Kingstowne says 7.2 UV, 833 watts/m^2

results in the shade with no cover

{ "tslLUX":"2152.00", "uvVIS":"312.00", "uvIR":"962.00", "uvUVRaw":"30.00", "uvUV":"0.30" }

{ "tslLUX":"2168.00", "uvVIS":"315.00", "uvIR":"976.00", "uvUVRaw":"31.00", "uvUV":"0.31" }

Kingstowne says 6.7 UV, 817 watts/m^2

This UV data shows a loss of about 5 and a half percent in the visible spectrum, 4 and a half percent considering the IR spectrum.  The overall percent difference between my local site and the site that I am using for calibration appears to be about 2.8 percent; my value is higher.  The distance between us is about 4.13 miles so I have been assuming that the values should be about the same.

According to this data, I should not have a problem if I used the lid to my sandwich container (plastic cover in the test).  I just have to compensate for the loss; there doesn't appear to be a loss associated with the UV sensitivity as far as I can tell.  So I should multiply my UV readings by 1.0628 to get the same as the Kingstowne values?  I should multiply my uvVIS values by 0.4979 to get the watts/m^2 equivalent to the values from the site where I am comparing my values.